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Ml aggarwal solutions

CHAPTERS

**A rectangle is 16 m by 9 m. Find a side of the square whose area equals the area of the rectangle. By how much does the perimeter of the rectangle exceed the perimeter of the square?**
**Solution:**

Area of rectangle = (16 × 9) m^{2} = 144 m^{2}

Given condition,

Area of square = Area of rectangle

∴ (Side)^{2} = 144

Side = √144 = 12 m

Now,

Perimeter of square = 4 × side = 4 × 12 = 48 m

Perimeter of rectangle = 2(l + b) = 2 (16 + 9) = 50 m

Hence, difference in their perimeters = 50 – 48 = 2 m

**A rectangle is 16 m by 9 m. Find a side of the square whose area equals the area of the rectangle. By how much does the perimeter of the rectangle exceed the perimeter of the square?**
**Solution:**

Area of rectangle = (16 × 9) m^{2} = 144 m^{2}

Given condition,

Area of square = Area of rectangle

∴ (Side)^{2} = 144

Side = √144 = 12 m

Now,

Perimeter of square = 4 × side = 4 × 12 = 48 m

Perimeter of rectangle = 2(l + b) = 2 (16 + 9) = 50 m

Hence, difference in their perimeters = 50 – 48 = 2 m

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