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Rs aggarwal solutions

CHAPTERS

3. Factorization of Polynomials

4. Linear Equations In Two Variables

6. Introduction To Euclids Geometry

9. Congruence Of Triangles And Inequalities In A Triangle

11. Areas Of Parallelograms And Triangles

14. Areas Of Triangles And Quadrilaterals

15. Volume And Surface Area Of Solids

A circus tent is cylindrical to a height of 3 metres and conical above it. If its diameter is 15m and the slant height of the conical portion is 53m, calculate the length of the canvas 5m wide to make the required tent.

ANSWER:

It is given that

Diameter of the cylinder = 105m

Radius of the cylinder = 105/2 = 52.5m

Height of the cylinder = 3m

Slant height of the cylinder = 53m

We know that

Area of canvas = 2 πRH + πRl

By substituting the values

Area of canvas = (2 × (22/7) × 52.5 × 3) + ((22/7) × 52.5 × 53)

On further calculation

Area of canvas = 990 + 8745 = 9735m2

We know that

Length of canvas = area/ width = 9735/5 = 1947m

**Therefore, the length of canvas required to make the tent is 1947m.**

ANSWER:

It is given that

Diameter of the cylinder = 105m

Radius of the cylinder = 105/2 = 52.5m

Height of the cylinder = 3m

Slant height of the cylinder = 53m

We know that

Area of canvas = 2 πRH + πRl

By substituting the values

Area of canvas = (2 × (22/7) × 52.5 × 3) + ((22/7) × 52.5 × 53)

On further calculation

Area of canvas = 990 + 8745 = 9735m2

We know that

Length of canvas = area/ width = 9735/5 = 1947m

**Therefore, the length of canvas required to make the tent is 1947m.**

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