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Rd sharma solutions

CHAPTERS

6. Algebraic Expressions and Identities

8. Division of Algebraic Expressions

9. Linear Equation in One Variable

10. Direct and Inverse Variations

13. Profit Loss Discount and Value Added Tax

15. Understanding Shapes Polygons

16. Understanding Shapes Quadrilaterals

17. Understanding Shapes Special Types Quadrilaterals

20. Area of Trapezium and Polygon

21. Volume Surface Area Cuboid Cube

22. Surface Area and Volume of Right Circular Cylinder

23. Classification And Tabulation Of Data

24. Classification And Tabulation Of Data Graphical Representation Of Data As Histograms

25. Pictorial Representation Of Data As Pie Charts Or Circle Graphs

A dealer bought two tables for Rs 3120. He sold one of them at loss of 15% andother at a gain of 36%. Then, he found that each table was sold for the same price.Find the cost price of each table.

Given, the cost price of two tables is = Rs 3120

Let cost price of first table be = Rs x

Then, cost price of second table will be = Rs 3120 – x

We know that one is a gain and other is a loss.

Selling price of first table (gain) = x + x × 36/100

= x +9x/25

= (25x + 9x)/25

= Rs 34x/25

Selling price of second table (loss) = (3120 - x) × 85/100

= Rs (3120×85 – 85x)/100

So now, by equating both we get,

34x/25 = (3120×85 – 85x)/100

34x = (3120×85 – 85x)/4

34x × 4 = 3120×85 – 85x

136x + 85x = 3120×85

221x = 3120×85

x = (3120×85)/221

= 1200

∴ Cost price of first table (x) is = Rs 1200

Cost price of second table (3120 - x) = 3120 – 1200 = Rs 1920

Algebraic Expressions and Identities

Division of Algebraic Expressions

Linear Equation in One Variable

Profit Loss Discount and Value Added Tax

Understanding Shapes Quadrilaterals

Understanding Shapes Special Types Quadrilaterals

Volume Surface Area Cuboid Cube

Surface Area and Volume of Right Circular Cylinder

Classification And Tabulation Of Data

Classification And Tabulation Of Data Graphical Representation Of Data As Histograms

Pictorial Representation Of Data As Pie Charts Or Circle Graphs

Given, the cost price of two tables is = Rs 3120

Let cost price of first table be = Rs x

Then, cost price of second table will be = Rs 3120 – x

We know that one is a gain and other is a loss.

Selling price of first table (gain) = x + x × 36/100

= x +9x/25

= (25x + 9x)/25

= Rs 34x/25

Selling price of second table (loss) = (3120 - x) × 85/100

= Rs (3120×85 – 85x)/100

So now, by equating both we get,

34x/25 = (3120×85 – 85x)/100

34x = (3120×85 – 85x)/4

34x × 4 = 3120×85 – 85x

136x + 85x = 3120×85

221x = 3120×85

x = (3120×85)/221

= 1200

∴ Cost price of first table (x) is = Rs 1200

Cost price of second table (3120 - x) = 3120 – 1200 = Rs 1920

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